Nolan Plots The Y Intercept

Solution:
Note: In this graph, the spacing of the hash marks on the 10 and y-axis are spaced almost identically.

Details:
To graph this line we demand to place the gradient and the y-intercept. The equation is written in slope-intercept form, \(y=mx+b\), where m is the slope and b is the y-intercept.

Footstep i: Find the slope and the y-intercept of the line:

The equation of the line is

\({\text{y}}={{\color{Red} -\text{x}}}{\colour{Blue}{-}iv}\)

Keep in mind that \({\colour{red}-}{\color{Ruby}{\text{10}}}\) is equal to \({\color{red}-1}{\color{Red}{\text{x}}}\), and so an equivalent equation is:

\({\text{y}}={\color{scarlet}-ane}{\text{ten}}{\colour{Blue}{-}4}\)

So the slope is \({\color{ruddy}-i}\), and the y-intercept is \({\colour{blue}-4}\)

Step 2: Graph the y-intercept:

This is a picture of a coordinate aeroplane with the point \((0,−4)\) graphed on it.

Step 3: Find another point on the line using the gradient:

The gradient is \(−1\), which we can rewrite as \(-\dfrac{1}{1}\). Gradient is \(\dfrac{\text{ascent}}{\text{run}}\), which means that to find some other betoken on the graph, we start at the y-intercept and then move downwardly 1 space, so ane infinite to the right:

This is a picture show of a coordinate plane with the points \((0,−4)\) and \((1,−5)\) graphed on it. There is an arrow pointing from \((−4,0)\) to \((−5,0)\) and an arrow pointing from \((−5,0)\) to \((1,-5)\)

Step 4: Describe a line that passes through the points:

This is a picture of a coordinate plane with the points \((0,−4)\) and \((1,−5)\) graphed on it. At that place is a line passing through both points.

Nolan Plots The Y Intercept,

Source: https://resourcecenter.byupathway.org/math/m14-09

Posted by: torresposelver.blogspot.com

Share this post